Penulis Topik: Probability  (Dibaca 1136 kali)

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Probability
« pada: Juli 20, 2018, 11:28:37 AM »
Moshi moshi.

I try to answer ... . I’m sorry if I wrong ... .

$n(S)=10^3\cdot(10\cdot9\cdot8)=72\cdot10^4$ ... .

$n(A)=6^3\cdot(6\cdot4\cdot3)=15552$ ... .

$\displaystyle{P(A)}=\frac{n(A)}{n(S)}=\frac{15552}{72\cdot10^4}\approx0,0216$ ... .

http://www.thescienceforum.com/mathematics/33981-probability.html#post399444

Syukur kepada Allah.



\[ \sum_{j=0}^\infty \frac{1}{j!(n-j)!} = \frac{2^n}{n!} \]