KAMP
Matematika => Fisika Matematik => Topik dimulai oleh: trfrm pada Juli 20, 2018, 11:28:37 AM
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I try to answer ... . I’m sorry if I wrong ... .
$n(S)=10^3\cdot(10\cdot9\cdot8)=72\cdot10^4$ ... .
$n(A)=6^3\cdot(6\cdot4\cdot3)=15552$ ... .
$\displaystyle{P(A)}=\frac{n(A)}{n(S)}=\frac{15552}{72\cdot10^4}\approx0,0216$ ... .
http://www.thescienceforum.com/mathematics/33981-probability.html#post399444